Modeling Weeds - Agricultural Systems - Numerical - Computer Lab - Assessment Answer
Assessment Task:
QUESTION 1
The following R code defines the same function given in Step 1 of the instructions – make sure you can clearly see why they are the same.
yieldprop = function(cropdensity,cropindex,weeddensity,weedindex){
cropcompfactor = cropdensity*cropindex
weedcompfactor = weeddensity*weedindex
QUESTION 2 -
How much difference to wheat yield does the model predict for increasing seeding rate from 100 to 200 plants per square metre in a weed-free paddock (tonnes per hectare)? (Record answers as positive numbers, being the difference in tonnes per hectare. Assume that maximum potential weed-free yield is 3 tonnes per hectare for this question and the following unless specified otherwise.
QUESTION 3-
How much difference to wheat yield does the model predict for increasing seeding rate from 100 to 200 plants per square metre if ryegrass is present at 33 plants per square metre? (tonnes per hectare)
QUESTION 4-
How much difference to wheat yield does the model predict for increasing seeding rate from 100 to 200 plants per square metre if ryegrass is present at 115 plants per square metre? (tonnes per hectare)
QUESTION 5-
Historical empirical data shows that 10 barley plants per square metre give half the maximum yield in a weed free paddock (rather than 11 as for wheat) ie the ‘size’ of a barley plant is 1/10 (instead of 1/11 for wheat). Recreate the graph for barley instead of wheat. The easiest way to do this is probably to copy and paste your code from above, and then adjust it (although if you are a good coder you might create a plotting function). Is barley more competitive than wheat ie. for a given weed density, do you get more yield with barley than wheat for the same crop density?
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